Home
Class 12
CHEMISTRY
The vapour pressure of mixture of toluen...

The vapour pressure of mixture of toluene and xylene at `90^(@)`C is 0.5 atm. If at this temperature 400 mm and 150 mm respectively then what will be the mole fraction of toluene in mixture ?

A

0.08

B

0.92

C

0.88

D

0.46

Text Solution

Verified by Experts

The correct Answer is:
B

`P_(s)=X_(A)P_(A)^(@)+(1-X_(A))P_(B)^(@)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution at 20^(@)C is composed of 1.5 mol of benzene and 3.5 mol of toluene. If the vapour pressure of pure benzene and pure toluene at this temperature are 74.7 torr and 22.3 torr, respectively, then the total vapour pressure of the solution and the benzene mole fraction in equilibrium with it will be, respectively: