Dissolving `120g` of urea `(Mw = 60)` in `1000 g` of water gave a solution of density `1.15 g mL^(-1)`. The molarity of solution is:

Options

A. 1.78 M
B. 2.00 M
C. 2.05 M
D. 2.22 M

Answer

C

Explanation

`m=(1000M)/(1000d-MMw)`
`(120)/(60)xx(1000)/(1000)=(1000M)/(1000xx1.5-M(60))`
`2.30xx1000-120M=1000M`
`M=(2.30xx1000)/(1120)=2.05`