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The vapour pressure of pure liquid solve...

The vapour pressure of pure liquid solvent A is `0.80` atm when a non volatile solute B is added to the solvent its vapours pressure falls to `0.60` atm. Mole fraction of solute B in the solution is:

A

0.75

B

0.5

C

0.25

D

0.33

Text Solution

Verified by Experts

The correct Answer is:
C
`X_(B)=(P^(@)-P_(s))/(P^(@))=(0.8-0.6)/(0.8)=(1)/(4)=0.25`
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