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The van't Hoff factor for 0.1 M Ba(NO(3)...

The van't Hoff factor for `0.1 M Ba(NO_(3))_(2)` solution is `2.74`. The degree of dissociation is

A

`91 .3%`

B

`87%`

C

`100%`

D

`74%`

Text Solution

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The correct Answer is:
B
`i=2.74`
`alpha=(i-1)/(n-1)=(2.74-1)/(3-1)=(1.74)/(2)=0.87`
`=87%`
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