The ratio of `t_(0.75)` and `t_(0.5)` for first order reaction :-

Options

A. `4:3`
B. `3:2`
C. `2:1`
D. `1:2`

Answer

C

Explanation

`(t_(0.75))/(t_(0.50))=((2.3)/(k)log(A_(0)/(0.25A_(0))))/((2.3)/(k)log(A_(0)/(0.5A_(0))))=(log(4))/(log2)=(2)/(1)`