Home
Class 12
CHEMISTRY
For a first order homogenous gaseous rea...

For a first order homogenous gaseous reaction, `Ato2B+C`
then initial pressure was `P_(i)` while total pressure after time 't' was `P_(t)`. The right expression for the rate constants k in terms of `P_(i),P_(t)` and t is :

A

`K=(2.303)/(t)log((2"Pi")/(3"Pi"-Pt))`

B

`K=(2.303)/(t)log((2"Pi")/(2P_(t)-P_(i)))`

C

`K=(2.303)/(t)log((P_(i))/(P_(i)-P_(t)))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

`{:(A ,to,28,+,C),("Pi",,0,,0),("Pi"-x,,2x,,x):}:|{:(),("Pi"-x+2x+x=P_(t)),(x=((P_(t)-P_(i)))/2):}`
`K=(2.303)/(t)"log"(P_(i))/(P_(i)-X)=(2.303)/(K)"log"(2P_(i))/(3P_(i)-P_(t))`
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle is thrown vertically upwards from the surface of the earth. Let T_(P) be the time taken by the particle to travel from a point P above the earth to its highest point and back to the point P. Similarly, let T_(Q) be the time taken by the particle to travel from another point Q above the earth to its highest point and back to the same in terms of T_(P), T_(Q) and H, is :-

Three moles of an ideal gas (C_p=7/2R) at pressure, P_A and temperature T_A is isothermally expanded to twice its initial volume. It is then compressed at constant pressure to its original volume. Finally gas is compressed at constant volume to its original pressure P_A . (a) Sketch P-V and P-T diagrams for the complete process. (b) Calculate the net work done by the gas, and net heat supplied to the gas during the complete process.

The equation of state of a real gas is given by (P+a/V^(2)) (V-b)=RT where P, V and T are pressure, volume and temperature resperature and R is the universal gas constant. The dimensions of the constant a in the above equation is

A cylinder of cross-section area. A has two pistons of negligible mass separated by distances l loaded with spring of negligible mass. An ideal gas at temperature T_(1) is in the cylinder where the springs are relaxed. When the gas is heated by some means its temperature becomes T_(2) and the springs get compressed by (l)/(2) each . if P_(0) is atmospheric pressure and spring constant k= (2P_(0)A)/(l) , then find the ratio of T_(2) and T_(1) .

Answer the following questions based on the P-T phase diagram of CO_(2) : What happens when CO_(2) at 4 atm pressure is cooled from room temperature at constant pressure ?

The arms of a U shaped tube are vertical. The arm on right side is closed and other arm is closed by light movable piston. There is mercury in the tube and initially the level of the mercury in the arms is the same. Above the mercury, there is an air column of height h in each arm, and initial pressure is the same as atmospheric pressure in both arms. Now pistion is slowly pushed down by a distance of h//2 (see figure) Let x is the displacement of mercury level in one of the stem and P_(1) is pressure in left column of air after compression, P_(2) is pressure in right column of air after compression and P_(0) is atmospheric pressure then

The population of a city increases at the rate 3% per year. If at time t the population of city is p, then find equation of p in time t.