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In a reaction N(2(g))+3H(2(g))to2NH(3(g)...

In a reaction `N_(2(g))+3H_(2(g))to2NH_(3(g))` rate of appearance of `NH_(3)` is `2.5xx10^(-4)molL^(-1)sec^(-1)` then rate of reaction and rate of disappearance of `H_(2)` respectively is :-

A

`3.75xx10^(-4),1.25xx10^(-4)`

B

`1.25xx10^(-4),2.5xx10^(-4)`

C

`1.25xx10^(-4),3.75xx10^(-4)`

D

`5xx10^(-4),3.75xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C

`ROR=(-d[N_(2)])/(dt)=(-d[H_(2)])/(3dt)=(d[NH_(3)])/(2dt)`
`ROR=(d[NH_(3)])/(2dt)`
`ROR=(2.5xx154)/(2)=1.25xx10^(-4)`
`(-d[H_(2)])/(dt)=(3)/(2)(d[NH_(3)])/(dt)=(3)/(2)xx2.5xx10^(-4)=3.75xx10^(-4)`
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