Reaction `A+BtoC+D` is started with 1 M of each A and B and follows the rate law
`r=k[A]^(1//2)[B]^(1//2)`
What is the time taken for the concentration of A to drop to 0.1 M `(K=2.303xx10^(-3)sec^(-1))`

Options

A. 57 sec
B. 100 sec
C. 434 sec
D. 1000 sec

Answer

D

Explanation

`A+BtoC+D`
`t=0 1M1M`
`r=k[A]^(1//2)[B]^(1//2)`
if initial concentration of A & B are same then `r=k (A)^(1)`
`(2.303)/(2.303xx10^(-3))"log"(1)/(0.1)=1000sec.`