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The activation energy for the reaction -...

The activation energy for the reaction -
`H_(2)O_(2)toH_(2)O+(1)/(2)O_(2)`
is `18 K cal//mol` at 300 K. calculate the fraction of molecules of reactonts having energy equal to or greater than activation energy ?
Anti log `(-13.02)=9.36xx10^(-14)`

A

`9.36xx10^(-14)`

B

`1.2xx10^(-12)`

C

`4.2xx10^(-16)`

D

`5.2xx10^(-15)`

Text Solution

Verified by Experts

The correct Answer is:
A
`e^((Eq)/(RT))=e(18000)/(2xx300)=e^(-30)`
`=9.36xx10^(-14)`
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