A uniform rope of length L is pulled by a constant force F. What is the tension in the rope at a distance l from the end where it is applied?

Explanation

Let mass of rope is M and T be tension in the rope at point P, then. Acceleration of rope, `a=(F)/(M)`
Equation of motion of part PB is F-T=(ml)a
`rArrT=F-(ml)a=F-((M)/(L))(l)((F)/(M))=[1-(l)/(L)]F`