A man weighs 80kg . He stands on a weigh...

A man weighs `80kg` . He stands on a weighing scale in a lift which is moving upwords with a uniform acceleration of `5m//s^(2)` . What would be the reading on the scale?

Zero

400N

88N

1200N

Text Solution

Verified by Experts

The correct Answer is:

`N-W=ma`
`therefore N=ma+W`
N is reading
`therefore` Reading `=80xx5+800=1200N`

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