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A cyclist on the ground goes round a cir...

A cyclist on the ground goes round a ciruclar path of circumference 34.3 m in `sqrt(22)` second. The angle made by him, with the vertical, will be:-

A

`45^(@)`

B

`40^(@)`

C

`42^(@)`

D

`48^(@)`

Text Solution

Verified by Experts

The correct Answer is:
A
`tan theta =(v^(2))/(rg)=(((34.3)/sqrt(22))^(2))/(((34.3)/(2pi))xx10)=1`
`therefore theta=45^(@)`
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