Home
Class 12
PHYSICS
A 0.5 kg ball moving with a speed of 12 ...

A `0.5 kg` ball moving with a speed of `12 m//s` strikes a hard wall at an angle of `30^(@)` with the wall. It is reflected with the same speed and at the same angle . If the ball is in contact with the wall for `0.25 s`, the average force acting on the wall is

A

48N

B

24N

C

12N

D

96N

Text Solution

Verified by Experts

The correct Answer is:
B
`F_("avg")=(Deltap)/(t)=(2mv sin 30^(@))/(0.25)`
`(2xx0.5xx12)/(1)xx(1)/(2)xx4=24N`
Promotional Banner

Topper's Solved these Questions

  • NEWTONS LAWS OF MOTION

    ALLEN |Exercise EXERCISE-II|112 Videos

  • NEWTONS LAWS OF MOTION

    ALLEN |Exercise EXERCISE-III|28 Videos

  • NEWTONS LAWS OF MOTION

    ALLEN |Exercise SWOE|44 Videos

  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN |Exercise EXERCISE (JA)|4 Videos

  • RACE

    ALLEN |Exercise Basic Maths (Wave Motion & Dopplers Effect) (Stationary waves & doppler effect, beats)|25 Videos

Similar Questions

Explore conceptually related problems

In cricket match, a bowler throws a ball of 0.5 kg with a speed of 20 m/s. When a batsman swings the bat the ball strikes with the bat normal to it, and returns in opposite direction with speed of 30 m/s. If the time of contact of the ball with the bat is 0.1s, then the force acting on the bat is......N.

A ball weighing 10g hits a hard surface vertically with a speed of 5m//s and rebounds with the same speed The ball remains in contact with the surface speed The ball remains in contact with the surface for 0.01s The average force exerted by the surface on the ball is .

A sphere of mass 4 kg collides with a wall, at an angle of 30^(@) with the wall and rebounds in the direction making an angle of 60^(@) with its original direction of motion. Find the force on the wall if the ball remains in contact with the wall for 0.1s. The initial and final velocities are the same, equal to 1ms^(-1)

A ball of mass 2 kg is moving with velocity 20 m/sec strikes with the surface and rebounds with same speed, if time of contact is 0.1 sec then calculate average force on the ball.

A 150 g ball, moving horizontally at 20m/s was hit straight back to bowler at 12m/s. If contact with bat lasted for 0.04 sec, then average force exerted by the bat on the ball is:-

A small ball is projected up a smooth inclined plane with an initial speed of 10 m//s along the direction at 30^(@) to the bottom edge of the slope .It returns to the edge after 2 s . The ball is in contact with the inclied plane throughout the process. The angle of inclination theta is :- .

A Rubber Ball Rebound A rubber ball of mass 2.0kg falls to the floor. The ball hits with a speed of 8m/s and rebounds with approximately the same speed. High speed photographs show that the ball is in contact with the floor for 10^-3s. What can we say about the force exerted on the ball by the floor?

A hammer of mass 1 kg moving with speed of 6 ms^(-1) strikes a wall and comes to rest in 0.1 s . Calculate (i) the impules of force (ii) the retardation of the hammer , and (iii) the retarding that stops the hammer .

A 100gm ball moving horizontally with 20m/s is struck by a bat, as a result it starts moving with a speed of 35m/s at an angle of 37 above the horizontal in the same verticle plane as shown in the figure. ltb/rgt (a) Find the average force exerted by the bat if duration of impact is 0.30s.ltb/rgt (b) FInd the average force exerted by the bat if duration of impact is 0.03s. (c) Find the average force exerted by the bat if duration of impact is 0.003s. (d) What do you conclude for impulse of weight of the ball as duration of contact decreases?

A 140g ball, in horizontal flight with a speed v_(1) of 39.0 m/s. is sturck by a bat. After leaving the bat, the ball travel in the opposite direction with speed v_(2)=39.0 m//s . If the impact time Deltat for the ball-bat collision is 1.20ms, what average net force acts on the ball

ALLEN -NEWTONS LAWS OF MOTION-EXERCISE-I
  1. A rocket of mass 1000 kg is to be projected vertically upwards. The ga...

    Text Solution

    |

  2. Three blocks of masses m(1),m(2)and m(3) are connected by massless str...

    Text Solution

    |

  3. A 0.5 kg ball moving with a speed of 12 m//s strikes a hard wall at an...

    Text Solution

    |

  4. A person used force (F) , shown in figure to move a load with constant...

    Text Solution

    |

  5. The ratio of gravitational mass to inertial mass is equal to:

    Text Solution

    |

  6. A given object takes n times as much time to slide down a 45^(@) rough...

    Text Solution

    |

  7. The figure shows a horizontal force vecF acting on a block of mass M o...

    Text Solution

    |

  8. A 150 g tenins ball coming at a speed of 40m/s is hit straight back by...

    Text Solution

    |

  9. Three solids of masses m(1),m(2) and m(3) are connected with weightles...

    Text Solution

    |

  10. Two blocks of masses M(1)=4 kg and M(2)=6kg are connected by a string ...

    Text Solution

    |

  11. Three masses M(1), M(2) and M(3) are lying on a frictionless table. Th...

    Text Solution

    |

  12. In Newton's second vecF=mveca (for constant mass m), veca is the accel...

    Text Solution

    |

  13. A man of mass 90kg is standing in an elevator whose cable broke sudden...

    Text Solution

    |

  14. A force vecF=(6hati-8hatj+10hatk)N produces acceleration of 1 ms^(-2) ...

    Text Solution

    |

  15. Two bodies A and B of masses 10kg and 15kg respectively kept on a smoo...

    Text Solution

    |

  16. Ten one-rupee coins are put on top of each other on a table, Each coin...

    Text Solution

    |

  17. A block of mass m is in contact with the cart C as shown in The coeffi...

    Text Solution

    |

  18. A gramphone record is revolving with an angular velocity omega. A coin...

    Text Solution

    |

  19. A man, of mass 60kg, is riding in a lift. The weights of the man, when...

    Text Solution

    |

  20. A person of mass 940 kg and presses the button on control panel. Then ...

    Text Solution

    |