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A gramphone record is revolving with an ...

A gramphone record is revolving with an angular velocity `omega`. A coin is placed at a distance `r` from the centre of the record. The static coefficient of friction is `mu`. The coin will revolve with the record if

A

`rge(mug)/(omega^(2))`

B

`r=(mug)/omega^(2)`

C

`rlt(omega^(2))/(mug)`

D

`rle(mug)/(omega^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
`mumgge(mv^(2))/(r)`
`rger^(2)`
`mumggemrw^(2)`
`rle(mug)/(w^(2))`
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