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A mass of 6 kg is suspended by a rope of...

A mass of 6 kg is suspended by a rope of length 2m from a celling. A force of 50N is applied in horizontal direction at the mid point of the rope. What is the angle of the rope with the verticle in equilibrium:-

A

`tan^(-1)((4)/(5))`

B

`tan^(-1)((5)/(4))`

C

`tan^(-1)((5)/(6))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`T cos theta=60`
`T sin theta=50`
`therefore tan theta=(5)/(6)`
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