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The frictional force of the air on the b...

The frictional force of the air on the body of mass 0.25kg, falling with an acceleration of 9.2 `m//s^(2)` will be `(g=9.8m//s^(2))`.

A

1.0N

B

0.55N

C

0.25N

D

0.15N

Text Solution

Verified by Experts

The correct Answer is:
D
`mg-f=ma`
`therefore f=m(g-a)=0.25xx0.6=0.15N`
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