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A block of mass m lying on a rough horiz...

A block of mass m lying on a rough horizontal plane is acted upon by a horizontal force P and another force Q inclined at an angle `theta` to the vertical. The minimum value of coefficient of friction of friction between the block and the surface for which the block will remain in equilibrium is

A

`(P+Q sin theta)/(mg+Qcos theta)`

B

`(P cos theta+Q)/(mg-Q sin theta)`

C

`(P+Q cos theta)/(mg+Q sin theta)`

D

`(Psin theta+Q)/(mg-Q cos theta)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Q cos theta+mg=N`
`P+Q sin theta=muN`
`therefore mu=(P+Qsin theta)/(Q cos theta+mg)`
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ALLEN -NEWTONS LAWS OF MOTION-EXERCISE-II
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