If 100N force is applied to 10kg. block as shown in diagram then acceleration produced for slab-

Options

A. `1.65 m//s^(2)`
B. `0.98 m//s^(2)`
C. `1.2 m//s^(2)`
D. `0.25 m//s^(2)`

Answer

B

Explanation

If move together
`a=(100)/(50)=2m//s^(2)`
`f_(s)("max")=100xx0.6=60N`
`f_(k)=100xx0.4=40N`
The force needed by 40kg=80N
`therefore` Relative motion takes place.
`therefore a_("slab")=(f_(k))/(M)=(40)/(40)=1m//s^(2)`