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On an X temperature scale, water freezes...

On an X temperature scale, water freezes at `-125.0^(@) X` and boils at `375.0^(@) X`. On a Y temperature scale, water freezes at `-70.0^(@)Y` and boils at `-30.0^(@)Y`. The value of temperature on X-scale equal to the temperature of `50.0^(@)Y` on Y-scale is

A

`455.0^(@)X`

B

`-125.0^(@)X`

C

`1375.0^(@)X`

D

`1500.0^(@)X`

Text Solution

Verified by Experts

The correct Answer is:
C
Let `theta`=temperature on `X`-scale corresponding to `50^(@)C` on `Y` - scale
`implies (X-(-125))/(375-(-125)) = (50-(-70))/(-30-(-70)) implies X=1375`
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Knowledge Check

  • In new temperature scale W, freezing point of water is 39^(@)W and boiling point is 239^(@)W . What would be the temperature on new temperature scale for 39^(@)C temperature ?

    A
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