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At 4^(@)C, 0.98 of the volume of a body ...

At `4^(@)C, 0.98` of the volume of a body is immersed in water. The temperature at which the entire body gets immersed in water is (neglect the expansion of the body ) (`gamma_(w) = 3.3 xx10 ^(-4)K^(-1)`):-

A

`40.8^(@)C`

B

`64.6^(@)C`

C

`60.6^(@)C`

D

`58.8^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
Let at temperature `theta` , volume increases by `2%` then
` 100=98[1+3.3xx10(theta-4)]`
`implies theta = 60.4 + 4 =64.4 ^(@)C`
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