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A steel scale measures the length of a c...

A steel scale measures the length of a copper rod as `l_(0)` when both are at `20^(@)C`, which is the calibration temperature for the scale . The scale reading when both are at `40^(@)C`, is :-

A

`(1 + 20alpha_(C))l_(0)`

B

`(1+20alpha_(S))l_(0)`

C

`((1+20alpha_(S))/(1+20alpha_(C)))l_(0)`

D

`((1+20alpha_(C))/(1+20alpha_(S)))l_(0)`

Text Solution

Verified by Experts

The correct Answer is:
D

`l_(0)(1+20 alpha_(C)) = l_(1) (1+20alpha_(S)) implies l_(1) = ((1+20alpha_(C))/(1+20alpha_(S)))l_(0)`
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ALLEN -GEOMETRICAL OPTICS-EXERCISE -01
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