Hailstone at `0^@C` from a height of 1 km on an insulating surface converting whole of its kinetic energy into heat. What part of it will melt? (`g=10 m//s`)

Options

A. `(1)/(33)`
B. `(1)/(8)`
C. `(1)/(33) xx 10^(-4)`
D. All of it will melt

Answer

A

Explanation

M= mass of hailstone falling
m = mass of hailstone melting
As Mgh = ml.
S0 `(m)/(M) = (gh)/(L) = (10 xx 10^(3))/(33 xx 10^(3)) = (1)/(33)`