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A mixture of n(1) moles of monoatomic ga...

A mixture of `n_(1)` moles of monoatomic gas and `n_(2)` moles of diatomic gas has `(C_(p))/(C_(V))=gamma=1.5`

A

`n_(1) = n_(2)`

B

`2n_(1) = n_(2)`

C

`n_(1) = 2n_(2)`

D

`2n_(1) = 3n_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
` gamma = (n_(1)C_(P1) + n_(2)C_(P2))/ (n_(1)C_(V1) + n_(2)C_(V2))`
` gamma = 1.5 therefore C_(P1) = (5R)/(2) , C_(P2) = (7R)/(2) `
` C_(V1) = (3R)/(2) , C_(V2) = (5R)/(2)` , then `n_(1) = n_(2)`
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