A man of height H is standing in front of an inclined plane mirror at an angle `theta` from horizontal. The vertical separation between man and inclined plane is x. Man can see its complete image in length `(H(H+x)"sin"theta)/(H +2x)` of mirror .
(Given : x = H = 1m and `theta = 45^(@)`)

If man starts moving with velocity `1 ms^(-1)` horizontally, find out length of mirror at t=1s in which he can see his complete image.

Options

A. (a)`sqrt(2)m`
B. (b)`(1)/(sqrt(2))m`
C. (c)`(1)/(2sqrt(2))m`
D. (d)`2 sqrt(2)m`

Answer

B

Explanation

In this case` x = 1-1 = 0`
so length of mirror = `(1(1+0)"sin"45^(@))/(1 +2 xx0) = (1)/(sqrt(2))`