A point object is placed `33cm` from a convex mirror of curvature radius `=40cm` A glass plate of thickness `6cm` and refractive index `2.0` placed between the object and mirror,close to the mirror,find the distance of final image form the object?

Answer

`sin^(-1)(1)/(sqrt(3))`

Explanation

`x= t(1- (1)/(mu))= 3 cm`
For mirror:
Object -`I_(1) : u =-30, f= 20`
`v = (-30 xx 20)/(-30-20)= 12 "cm" = 33 + 9 = 42 "cm"`
from object