In the figure shown L is converging lens of focal length 10 cm and M is a concave mirror of radius of curvature 20 cm . A point object O is placed in front of the lens at a distance 15 cm . AB and CD are optical axes of the lens mirror respectively. Find the coordinates of the final image formed by this system taking O as origin. The distance between CD & AB is 1mm.

Answer

(-15 cm , -6mm)

Explanation

Image formed by the lens `v= (-15 xx10)/(-15 + 10) = 30`
(Right from lens)
Reflection from mirror u = -15
`v = (-15 xx 10)/(-15 + 10) = -30 , m = ((-30))/(-15) = -2`
Co-ordinate of image = `(30, 0.3 cm)`
Now again taking refraction from lens )
`v= (-15 xx 10)/(-15 + 10) = 30` (left from lens) m= `(30)/(-15) = -2`
`therefore` Final co-ordinate of image = (-15 cm, - 6mn)