A ray of light is incident at the glass-water interface at an angle I, it emerges fimally parallel to the surface of water, the the value of `mu_g` would be

Options

A. (4/3) sin i
B. 1/sin i
C. `4//3`
D. 1

Answer

B

Explanation

Applying Snell's law `(mu "sini"` = constant ) at 1 and 2 , we have `mu_(1) "sini" i_(1) = mu_(2) "sin"i_(2)`

Here `mu_(1) = mu_("glass"), i_(1) = I, mu_(2) = mu_("air") = 1 "and" i_(2) = 90^(@)`
`therefore mu_(g) "sin"i = (1)("sin"90^(@)) "or" mu_(g) = (1)/("sin i")`