Passage IV) Angular frequency in SHM is given by `omega=sqrt(k/m)`. Maximum acceleration in SHM is `omega^(2)` A and maximum value of friction between two bodies in contact is `muN`, where N is the normal reaction between the bodies.
Now the value of k, the force constant is increased, then the maximum amplitude calcualted in above question will
Passage IV) Angular frequency in SHM is given by `omega=sqrt(k/m)`. Maximum acceleration in SHM is `omega^(2)` A and maximum value of friction between two bodies in contact is `muN`, where N is the normal reaction between the bodies.
Now the value of k, the force constant is increased, then the maximum amplitude calcualted in above question will
Now the value of k, the force constant is increased, then the maximum amplitude calcualted in above question will
A
remain same
B
increase
C
decrease
D
data in insufficient
Text Solution
Verified by Experts
The correct Answer is:
C
`omega^(2) = "constant" rArr A prop 1/k`
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