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Two particles A and B are performing SHM...

Two particles A and B are performing SHM along x and y-axis respectively with equal amplitude and frequency of `2 cm` and `1 Hz` respectively. Equilibrium positions of the particles A and B are at the coordinates `[3 cm, 0]` and `(0, 4 cm)` respectively. At `t = 0 ,B` is at its equilibrium position and moving towards the origin, while A is nearest to the origin and moving away from the origin-
Equation of motion of particle A can be written as-

A

`y = (2 cm) cos 2 pit`

B

`y = (4 cm) - (2 cm) cos 2pit`

C

`y = (2 cm) sin 2 pit`

D

`y = (4 cm) - (2 cm) sin 2pit`

Text Solution

Verified by Experts

The correct Answer is:
D
As B is at its equilibrium position and moving towards negative exterme at `t = 0`
so `y-4 = 0.2 sin (2pit + pi) rArr y= 4 -2 sin (2pit)`
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