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The shortest distance travelled by a par...

The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to `(sqrt(3)//2)` times its amplitude. Determine its time period.

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The correct Answer is:
A, B
`:' y = Asinomegat = Asin'(2pi)/(T) t`
`:. (sqrt(3))/(2) A = Asin((2pi)/(T) xx 2) = Asin ((4pi)/(T))`
`rArr (4pi)/(T) = (pi)/(3) rArr T = 12 s`
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