A body executing `S.H.M`. has its velocity `10cm//s` and `7 cm//s` when its displacement from the mean positions are `3 cm` and `4 cm` respectively. Calculate the length of the path.

Answer

B, C

Explanation

Velocity `v = omega sqrt(a^(2) - x^(2))`
`:. (v_(2))/(v_(1)) = (sqrt(a^(2) - x_(2)^(2)))/(sqrt(a^(2) - x_(1)^(2))) rArr (49)/(100) = (a^(2) - 16)/(a^(2) - 9)`
`rArr a = - 4.76 cm`
`rArr ` length of path `= 2a = 9.52 cm`