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Calculate the time period of a uniform s...

Calculate the time period of a uniform square plate of side `'a'` if it is suspended through a corner.

Text Solution

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The correct Answer is:
A, B, C
`T = 2pisqrt((l)/(mgl))`

`2pisqrt(((ma^(2))/(6)+(ma^(2))/(2))/(mg(a/(sqrt(2))))`
`= 2pisqrt((2sqrt(2)a)/(3g))`
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ALLEN -SIMPLE HARMONIC MOTION-Exercise-04 [A]
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  7. A particle executing a linear SHM has velocities of 8 m/s, 7 m/s and 4...

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  8. A particle is oscillating in a stright line about a centre of force O,...

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  9. The displacement of a particle varies with time as x = 12 sin omega t ...

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  10. A point particle if mass 0.1 kg is executing SHM of amplitude 0.1 m. W...

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  11. A body of mass 1 kg suspended an ideal spring oscillates up and down. ...

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  12. The potential energy (U) of a body of unit mass moving in a one-di...

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  13. A body of mass 1.0 kg is suspended from a weightless spring having for...

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  15. A block of mass 1kg hangs without vibrations at the end of a spring wi...

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  16. A small ring of mass m(1) is connected by a string of length l to a sm...

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  18. Two identical rods each of mass m and length L, are tigidly joined and...

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