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A particle at the end of a spring execut...

A particle at the end of a spring executes simple harmonic motion with a period `t_(1)` while the corresponding period for another spring is `t_(2)` if the oscillation with the two springs in series is T then

A

`T = t_(1) + t_(2)`

B

`T^(2) = t_(1)^(2) + t_(2)^(2)`

C

`T^(-1) = t_(1)^(-1) + t_(2)^(-1)`

D

`T^(-2) = t_(1)^(-2) + t_(1)^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`T = 2pisqrt((m)/(k)) rArr T^(2) prop (1)/(k)`
`t_(1)^(2) prop 1/(k_(1))` & `t_(2^(2)) prop (1)/(k_(2)) rArr t_(1)^(2) prop (1)/(k_(1)) + (1)/(k_(2))`
But `(1)/(k_(1)) + (1)/(k_(2)) = (1)/(k) prop T^(2) rArr t_(1^(2)) + t_(2^(2)) = T^(2)`
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