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A particle executes simple harmonic moti...

A particle executes simple harmonic motion between `x = -A and x = + A`. The time taken for it to go from `0 to A//2` is `T_1` and to go from `A//2 to A` is `T_2`. Then.

A

(a)`T_(1) lt T_(2)`

B

(b)`T_(1) gt T_(2)`

C

(c)`T_(1) = T_(2)`

D

(d)`T_(1) = 2T_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
In SHM, velocity of particle also oscillated simple harmonically. Speed is more near the mean position and less near the extreme position. Therefore, the time taken for the particle to go from O to `A//2` will be less than the time taken to go it from `A//2` to `T_(1) lt T_(2)`.
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