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In a Coolidege tube experiment, the mini...

In a Coolidege tube experiment, the minimum wavelength of the continuouse X-ray spectrum is equal to `66.3` om . Then

A

electrons accelerate through a potential difference of `12.75 kV` in the Coolidge tube

B

electrons accelerate through a potential difference of `18.75 kV` in the Coolidge tube

C

de-Broglie wavelength of the electrons reaching the anticathode is of the order of `10 "pm"`

D

de-Broglie wavelength of the electrons reaching the anticathode is `0.01 Å`

Text Solution

Verified by Experts

The correct Answer is:
B
`V=(12400)/(lambda_(min))xx10^(-10)` volt
`V=(12400xx10^(-10))/(66.3xx10^(-12))` volt `=12.4/66.3 xx10^(4)=18.75 kV`
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Knowledge Check

  • An X ray tube is operated at 50kV, the maximum wavelength produced is……..A.

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    B
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    D
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    C
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