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The neutron is a particle with zero char...

The neutron is a particle with zero charge still it has a non-zero magnetic moment with z-component `9.66 xx 10^(-27) A-m^(2)`. This can be explained by the internal structure of the neutron. The evidence indicates that a neutron is composed of three fundamental particles calleed quarks : an `"up"` (u) quark, of charge `+ (2e)/(3)`, and two `"down"` (d) quarks, each of change `- (e)/(3)`. The combinations of the three quarks prodcues a net charge of `(2e)/(3) - e/3 - e/3 = 0`.

If the quarks are in motion they can produce a non-zero magnetic moment. As a very simple model, suppose the u quark moves in a counter clockwise circular path and the d quarks move in a clockwise circular path, all of the radius r and all with the same speed v see figure.
The current due to the circular motion of the u quark :-

A

`(ev)/(6pir)`

B

`(ev)/(3pir)`

C

`(ev)/(pir)`

D

`(2ev)/(pir)`

Text Solution

Verified by Experts

The correct Answer is:
B
`i=qf=((2e)/3)(v/(2pir))=(ev)/(3pir)`
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The neutron is a particle with zero charge still it has a non-zero magnetic moment with z-component 9.66 xx 10^(-27) A-m^(2) . This can be explained by the internal structure of the neutron. The evidence indicates that a neutron is composed of three fundamental particles calleed quarks : an "up" (u) quark, of charge + (2e)/(3) , and two "down" (d) quarks, each of change - (e)/(3) . The combinations of the three quarks prodcues a net charge of (2e)/(3) - e/3 - e/3 = 0 . If the quarks are in motion they can produce a non-zero magnetic moment. As a very simple model, suppose the u quark moves in a counter clockwise circular path and the d quarks move in a clockwise circular path, all of the radius r and all with the same speed v see figure. Determine the magnitude of the three-quark system :-

The neutron is a particle with zero charge still it has a non-zero magnetic moment with z-component 9.66 xx 10^(-27) A-m^(2) . This can be explained by the internal structure of the neutron. The evidence indicates that a neutron is composed of three fundamental particles calleed quarks : an "up" (u) quark, of charge + (2e)/(3) , and two "down" (d) quarks, each of change - (e)/(3) . The combinations of the three quarks prodcues a net charge of (2e)/(3) - e/3 - e/3 = 0 . If the quarks are in motion they can produce a non-zero magnetic moment. As a very simple model, suppose the u quark moves in a counter clockwise circular path and the d quarks move in a clockwise circular path, all of the radius r and all with the same speed v see figure. Determine the magnitude of the magnetic moment due of the circular u quark :-

The neutron is a particle with zero charge still it has a non-zero magnetic moment with z-component 9.66 xx 10^(-27) A-m^(2) . This can be explained by the internal structure of the neutron. The evidence indicates that a neutron is composed of three fundamental particles calleed quarks : an "up" (u) quark, of charge + (2e)/(3) , and two "down" (d) quarks, each of change - (e)/(3) . The combinations of the three quarks prodcues a net charge of (2e)/(3) - e/3 - e/3 = 0 . If the quarks are in motion they can produce a non-zero magnetic moment. As a very simple model, suppose the u quark moves in a counter clockwise circular path and the d quarks move in a clockwise circular path, all of the radius r and all with the same speed v see figure. If all Quarks start moving in the same direction then what will be the magnetic moment of the neutron :-

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