If `13.6 eV` energy is required to ionized the hydrogen atom then , then the energy required to remove an electron from `n = 2 ` is

Options

A. (a)`10.2 eV`
B. (b)`0 eV`
C. (c)`3.4 eV`
D. (d)`6.8 eV`

Answer

C

Explanation

Energy required to lonize a atom from `n^(th)` orbit is
`= +13.6/n^(2) eV`
`E_(2)=(+13.6)/2^(2) eV= +3.4 eV`