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A radiation of energy 'E' falls normally...

A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (c = Velocity of light) :

A

`E//c`

B

`2E//c`

C

`Ec`

D

`E//c^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Total change in momentum from a reflecting surface `=2P`

The momentum of incident radiation `P=(2E)/c`
Hence, momentum transferred `=(2E)/c`
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