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If the source of power 4 kW produces 1...

If the source of power ` 4 kW` produces `10^(20)` photons/second , the radiation belongs to a part spectrum called

A

(a)`gamma-`rays

B

(b)`X-`rays

C

(c)ultraviolet rays

D

(d)microwaves

Text Solution

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The correct Answer is:
B
No. of photons emitting per second from a source of power P is `n=(5xx10^(24))Plambda`
`implies` wavelength emitting `lambda=(n)/((5xx10^(24))P)["or "lambda=(nhc)/P]`
`implies lambda= 10^(20)/(5xx10^(24)xx4xx10^(3))=0.5xx10^(-9)m=50 Å`
and this wavelength comes in X ray region
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