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Per nucleon energy of .(3)Li^(2) and .(2...

Per nucleon energy of `._(3)Li^(2)` and `._(2)He^(4)` nucleus is `5.60 MeV` and `7.06 MeV`, then in `._(3)Li^(7) + ._(1)P^(1) rarr 2_(2)He^(4)` energy relased is 10:12 PM-

A

`28.24 MeV`

B

`17.28 MeV`

C

`1.46 MeV`

D

`1.46 MeV`

Text Solution

Verified by Experts

The correct Answer is:
B
In a nuclear reaction the energy remains conservest
`P + ._(3)^(7)Li rarr 2(._(2)^(4)He)`
energy of proton `+ 7(5.60) = 2(4 xx 7.06)`
`rArr` energy of `= 17.28 MeV`
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