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A nucleus of mass M + Deltam is at rest ...

A nucleus of mass `M + Deltam` is at rest and decays into two daughter nuclei of equal mass `M/2` each. Speed of light is C.
The speed of deughter nuclei is :-

A

`csqrt((Deltam)/(M+mDeltam))`

B

`c(Deltam)/(M+Deltam)`

C

`csqrt((2Deltam)/(M))`

D

`csqrt((Deltam)/(M))`

Text Solution

Verified by Experts

The correct Answer is:
C

Total kinetic energy of products
`=` Total energy released `(P^(2))/(2m) + (P^(2))/(2m)`
= {mass defect) `c^(2)` (where `m = (M)/(2)` given)
`rArr 2(P^(2))/(2m) = [(M + Deltam) - ((M)/(2) + (M)/(2))] xx c^(2)`
`2 xx [(P^(2))/(2 ((M)/(2)))] = (Delta m)c^(2)`
`rArr (2((M)/(2)v)^(2))/(M) = (Delta m)c^(2) rArr v = c sqrt((2 Delta m)/(M))`
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