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After absorbing a slowly moving neutrons...

After absorbing a slowly moving neutrons of mass `m_(N)` (momentum ~0) a nucleus of mass M breaks into two nucleii of mass `m_(1) and 5m_(1)(6m_(1)=M+m_(N))`, respectively . If the de-Broglie wavelength of the nucleus with mass `m_(1) ` is ` lambda`, then de Broglie wavelength of the other nucleus will be

A

(a)`25 lambda`

B

(b)`5 lambda`

C

(c)`(lambda)/(5)`

D

(d)`lambda`

Text Solution

Verified by Experts

The correct Answer is:
D

According to Conservation of linear momentum `P=P`. Therefore `lambda'=lambda`
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