A particle of mass ` M ` at rest decays into two particles of masses `m_(1)` and `m_(2) `having non-zero velocities. The ratio of the de Broglie wavelengths of the particles 1 and 2 is

Options

A. (a)`m_(1)//m_(2)`
B. (b)`m_(2)//m_(1)`
C. (c)`1`
D. (d)`sqrt(m_(2))//sqrt(m_(1))`

Answer

C

Explanation

From law of conservation of momentum,
`P_(1)=P_(2)` (in opposite directions)
Now de-Brogli wavelength is given by `lambda=h/p`
[h=Plank's constant]
since, momentum (p) of both the particles is equal therefore `lambda_(1)=lambda_(2)implies lambda_(1)//lambda_(2)=1`