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The potential difference applied to an X...

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons stricking the target per second is ...... (Take `e=1.6xx10^(-19)C)`

A

`2 xx 10^(14)`

B

`5 xx 10^(6)`

C

`1 xx 10^(12)`

D

`4 xx 10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
A
`i=q/t=(n e)/t implies n= (I t)/e`
Substituting `=3.2xx10^(-3) A`
`e=1.6xx10^(-19) C` and `t=1 s`
We get, `n=2xx10^(16)`
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