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Kalpha wavelength emitted by an atom of ...

`K_alpha` wavelength emitted by an atom of atomic number Z=11 is `lambda`. Find the atomic number for an atom that emits `K_alpha` radiation with wavelength `4lambda`.
(a) Z=6 (b) Z=4
(c ) Z=11 (d) Z=44.

A

`Z = 6`

B

`Z = 4`

C

`Z = 11`

D

`Z = 44`

Text Solution

Verified by Experts

The correct Answer is:
A
`1/lambda prop (Z-1)^(2) :. lambda_(1)/lambda_(2)=((Z_(1)-1)/(Z_(1)-1))^(2)implies 1/4=((Z_(2)-1)/(11-1))^(2)`
solving this, we get `Z_(2)=6`
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