A hydrogen atom in its ground state is irradiated by light of wavelength `970Å` Taking `hc//e = 1.237 xx 10^(-6)`eV m and the ground state energy of hydrogen atom as ` - 13.6 eV` the number of lines present in the emmission spectrum is

Answer

6

Explanation

`(hc)/lambda=12370/970`
`-13.6+12.7= -13.6/n^(2)`
`n^(2)=16`
`n=4`
Number of lines `= .^(n)C_(2)=6`