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A car starts from rest with a constant t...

A car starts from rest with a constant tangential acceleration `a_(0)` in a circular path of radius r. At time t, the car kids, find the value of coefficient of friction.

Text Solution

Verified by Experts

The tangential and centripetal acceleration is provided only by the frictionless force.
`Thus, f sin theta, fcos theta=(mv^(2))/(r)=(m(a_(0)t)^(2))/(r)`
`Rightarrow f=m sqrt(a_(0)^(2)+((a_(o)t)^(4))/(r^(2)))=ma_(0)sqrt(1+a_(0)^(2)t^(4))/(r_(2))=f_("max")`
`mumg=ma_(0) sqrt(1+(a_(0)^(2)t^(4))/(r^(2))) Rightarrow mu=(a_(0))/(g)sqrt(1+(a_(0)^(2)t^(2))/(r^(2)))`
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