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A particle is revolving in a circle of r...

A particle is revolving in a circle of radius 1 m with an angular speed of 12 rad/s. At t = 0, it was subjected to a constant angular acceleration `alpha` and its angular speed increased to `(480/pi)` rotation per minute (rpm) in 2 sec. Particle then continues to move with attained speed. Calculate
(i) angular acceleration of the particle,
(ii) tangential velocity of the particle as a function of time.

Text Solution

Verified by Experts

The correct Answer is:
(i) `2 rad//s^(2)` (ii) `12+2t` for `t le 2s, 16` for `t ge 2s` (iii) `a = 169.01 m//s^(2)`,324 (iv) 44 rad
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