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Let a point P lies inside an equilater...

Let a point P lies inside an equilateral `triangle ABC` such that its perpendicular distances from sides are `P_(1),P_(2),P_(3)`.If side length of `triangle ABC` is 2 unit then

A

`(P_(1)+P_(2)+P_(3))` is equal to `sqrt(3)`

B

`(P_(1)+P_(2)+P_(3))` is equal to `4sqrt(3)`

C

Area of `triangle=sqrt(3)` Sq unit

D

Area of `triangle ABC =3` Sq unit

Text Solution

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The correct Answer is:
A, C
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Knowledge Check

  • The area of an equilateral triangle with each side measuring 10 cm is …………. cm^(2)

    A
    `(5sqrt(3))/(2)`
    B
    `25 sqrt(3)`
    C
    `5 sqrt(3)`
    D
    `3 sqrt(5)`
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