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The sum of n terms of an A.P is 715 .If ...

The sum of `n` terms of an A.P is `715` .If first term is increased by 1, second term is increased by 3, third term is increased by 5 and so on `k^(th)` term is increased by `k^(th)` odd integer then sum of `n` tems is `836` then value of `(n/6)` is

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The correct Answer is:
`1.83`
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